To build the Taylor polynomial we need the higher-order derivatives: the second derivative, the third, and in general the nn-th derivative.

Definition — nn-th derivative

The second derivative of ff is the derivative of the derivative: f(x)=(f(x))f''(x) = (f'(x))'. More generally, the nn-th derivative is obtained by differentiating nn times: f(n)(x)f^{(n)}(x). By convention f(0)(x)=f(x)f^{(0)}(x) = f(x).

Example — Higher-order derivatives of exe^x and sinx\sin x

Let f(x)=exf(x) = e^x. f(x)=exf'(x) = e^x, f(x)=exf''(x) = e^x, …, f(n)(x)=exf^{(n)}(x) = e^x for every nn.

Let f(x)=sinxf(x) = \sin x. f(x)=cosxf'(x) = \cos x, f(x)=sinxf''(x) = -\sin x, f(x)=cosxf'''(x) = -\cos x, f(4)(x)=sinxf^{(4)}(x) = \sin x, and then it repeats (cycle of period 44).

Topics: Derivatives
Concepts: Derivative · Higher-order derivative
Skills: Differentiating