The proof uses the chord theorem applied to the circle circumscribed about the triangle.

Proof — With the chord theorem

Consider the circle circumscribed about the triangle. The side aa is a chord of this circle, and the opposite angle A^\widehat{A} is the inscribed angle subtending the arc BCBC. By the chord theorem, a=2RsinA^,a = 2R\sin\widehat{A}, whence a/sinA^=2Ra/\sin\widehat{A} = 2R. Likewise for bb and cc: all three ratios equal 2R2R. \blacksquare

Topics: Triangle trigonometry
Concepts: Circumscribed circle · Sine rule · Chord theorem
Functions: Sine
Skills: Proving