The divisibility rules are not magic tricks: they all arise from the study of remainders, that is, from congruences.

Remark — The idea behind the proof

The rule for 33 (and for 99) follows from 101(mod3)10\equiv 1\pmod 3: every power of 1010 is 1\equiv 1, so a number aka1a0=ai10iai(mod3)\overline{a_k\ldots a_1 a_0}=\sum a_i\,10^i\equiv\sum a_i\pmod 3, that is, it has the same remainder as the sum of its digits. The rule for 1111 follows instead from 101(mod11)10\equiv -1\pmod{11}: we have 10i(1)i10^i\equiv(-1)^i, from which the alternating difference of the digits.

Congruences will be taken up systematically later on, in the study of number theory linked to RSA cryptography.

Topics: Numbers and operations
Concepts: Congruence · Divisibility rules · Divisibility
Skills: Prove